# Comments on Profile Post by MarioKart7z

1. Chazm
Simply; i. That's all this equation has to offer. However, if the minus were to be placed outside of the operation, then this equation would become 1 itself.

also you chose a godamn good day to give me maths, I'm still recovering from a cold
Jan 21, 2016
2. Jan 21, 2016
3. Chazm
i stands for Imaginary in Maths- and it's only obtainable with this or any even powered root of -1.
Jan 21, 2016
4. MarioKart7z
then what about sqrt(sqrt(sqrt(8569798\29009895023452834*38891982384890102-9949019038401234+4898929039054801234)))
Jan 21, 2016
5. Chazm
Triple sqrt can be simplified to 6^rt

then presume that the division is fractioned and that the entire equation below is as the denominator

and then of course, an extremely small number results. Something with the result of 6^rt(~10^-28.) - which happens to be ~2x10^-5.
Jan 21, 2016
6. MarioKart7z
darn, my math level is only -5488120549 while yours is 54990203954802939490020395+e5992938548
Jan 21, 2016
7. Chazm
Well. I'd like to see your calculations.

According to the new GCSE spectrum I'm around a grade 8 at the moment (A* in old GCSE terms)
Jan 21, 2016
8. MarioKart7z
my calculations are all basically "an expression? no not the expressions! too lazy to do expressions!"
Jan 21, 2016